Rotate an array of n elements to the right by k steps.
For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4].
Note: Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem.
Could you do it in-place with O(1) extra space?
要点: 数组中部分元素交换三次 (0, n-1), (0, k-1), (k-, n-1);
Edge cases: [1,2], k=4
private void reverse(int[] nums, int start, int end) {
while (start<end) {
int temp = nums[start];
nums[start] = nums[end];
nums[end] = temp;
start++;
end--;
}
}
public void rotate(int[] nums, int k) {
k = k % nums.length;
reverse(nums, 0, nums.length-1);
reverse(nums, 0, k-1);
reverse(nums, k, nums.length-1);
}