Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors.
OJ's undirected graph serialization: Nodes are labeled uniquely.
We use # as a separator for each node, and , as a separator for node label and each neighbor of the node. As an example, consider the serialized graph {0,1,2#1,2#2,2}.
The graph has a total of three nodes, and therefore contains three parts as separated by #.
- First node is labeled as 0. Connect node 0 to both nodes 1 and 2.
- Second node is labeled as 1. Connect node 1 to node 2.
- Third node is labeled as 2. Connect node 2 to node 2 (itself), thus forming a self-cycle.
Visually, the graph looks like the following:
1 / \ / \ 0 --- 2 / \ \_/
Use BFS to copy each visited node and its neighbors, the key is to use a map to track already copied node in the graph.
public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) {
if (node==null) {
return node;
}
//BFS
Queue<UndirectedGraphNode> queue = new LinkedList<UndirectedGraphNode>();
//map is used to store original map -> copied map
Map<UndirectedGraphNode, UndirectedGraphNode> copiedMap = new HashMap<UndirectedGraphNode, UndirectedGraphNode>();
UndirectedGraphNode newNode = new UndirectedGraphNode(node.label);
queue.add(node);
copiedMap.put(node, newNode);
while (!queue.isEmpty()) {
UndirectedGraphNode current = queue.poll();
List<UndirectedGraphNode> neighbors = current.neighbors;
for (UndirectedGraphNode neighbor : neighbors) {
UndirectedGraphNode copiedNode = copiedMap.get(neighbor);
//never visited before
if (copiedNode==null) {
copiedNode = new UndirectedGraphNode(neighbor.label);
//map the new node with original node
copiedMap.put(neighbor, copiedNode);
//enqueue the neighbor
queue.add(neighbor);
}
//either a loop or a different node, copy all neighbors
copiedMap.get(current).neighbors.add(copiedNode);
}
}
return newNode;
}